// Solving ax^2 + bx + c = 0
#include <iostream>
#include <math.h>
using namespace std;

const double a=1., b=3., c=-4.; 

int main()
{
  double D = b*b-4.*a*c; // determinant (local variable)

  if (D>=0){
    double x1 = (-b + sqrt(D))/(2.*a); // 1st root (local variable)
    double x2 = (-b - sqrt(D))/(2.*a); // 2nd root (local variable)
    cout << x1 << " " << x2 << endl;
  }
}